Triangle Perimeter Problem Solving For Stage Prop Edges

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Hey guys! Have you ever wondered how much material you need to decorate something, like a cool triangular stage prop? Well, let's dive into a fun math problem that's all about figuring out the perimeter of a triangle. This is super useful in real life, whether you're painting, building, or just decorating. Let's break it down!

Understanding the Problem

So, here’s the deal: Kat is painting the edge of a triangular stage prop with some awesome reflective orange paint. We know the lengths of the edges are given by the expressions (3xβˆ’4)(3x - 4) feet, (x2βˆ’1)(x^2 - 1) feet, and (2x2βˆ’15)(2x^2 - 15) feet. Our mission, should we choose to accept it, is to find the actual perimeter of this triangle. But, there's a catch! We need to figure out the value of 'x' first. No sweat, we can totally do this!

Setting Up the Equation

The key here is that a triangle's sides have to play nice together. No one side can be longer than the sum of the other two sides. This is known as the triangle inequality theorem. It’s like the golden rule for triangles! But, for now, to find a possible value for 'x,' we need to assume that these sides actually form a triangle. To do that, we first need to realize that the sides of a triangle must add up in a way that makes sense. It turns out that the perimeter of a triangle is simply the sum of the lengths of its three sides. So, if we add up the expressions for the lengths of the sides, we should get a meaningful expression for the perimeter.

The perimeter P of the triangle can be expressed as:

P=(3xβˆ’4)+(x2βˆ’1)+(2x2βˆ’15)P = (3x - 4) + (x^2 - 1) + (2x^2 - 15)

Let's simplify this:

P=3xβˆ’4+x2βˆ’1+2x2βˆ’15P = 3x - 4 + x^2 - 1 + 2x^2 - 15

Combine those like terms, and we get:

P=3x2+3xβˆ’20P = 3x^2 + 3x - 20

Okay, great! We have an expression for the perimeter, but we still don't know what 'x' is. This is where the tricky part comes in. We need to find a value for 'x' that makes all the side lengths positive because you can't have a side with a negative length. That would be like trying to build a fence with negative wood – totally impossible!

Finding the Value of 'x'

To find 'x,' we need to consider the constraints on the side lengths. Each side length must be greater than zero. This gives us three inequalities:

  1. 3xβˆ’4>03x - 4 > 0
  2. x2βˆ’1>0x^2 - 1 > 0
  3. 2x2βˆ’15>02x^2 - 15 > 0

Let's tackle these one by one. For the first inequality, 3xβˆ’4>03x - 4 > 0, we add 4 to both sides and then divide by 3:

3x>43x > 4

x>43x > \frac{4}{3}

So, 'x' must be greater than 1.33 (approximately). That's our first clue!

Now, let's look at the second inequality, x2βˆ’1>0x^2 - 1 > 0. This one is a bit more interesting. We can factor the left side:

(xβˆ’1)(x+1)>0(x - 1)(x + 1) > 0

This inequality holds true when both factors are positive or both are negative. This means either x>1x > 1 or x<βˆ’1x < -1. Since we're dealing with lengths, we can ignore the negative solution because 'x' has to be positive in our context. So, we have x>1x > 1.

Finally, let's handle the third inequality, 2x2βˆ’15>02x^2 - 15 > 0. We can rearrange this to get:

2x2>152x^2 > 15

x2>152x^2 > \frac{15}{2}

x2>7.5x^2 > 7.5

Taking the square root of both sides, we get:

x>7.5x > \sqrt{7.5} or x<βˆ’7.5x < -\sqrt{7.5}

Again, we only care about the positive solution, so x>7.5x > \sqrt{7.5}, which is approximately x>2.74x > 2.74.

Combining the Inequalities

Okay, we've got three conditions for 'x':

  • x>43x > \frac{4}{3} (approximately 1.33)
  • x>1x > 1
  • x>7.5x > \sqrt{7.5} (approximately 2.74)

To satisfy all these conditions, 'x' must be greater than 2.74. So, let's think about integer values for 'x'. The smallest integer value that fits the bill is x=3x = 3. Let's see if this works!

Testing x = 3

Plug x=3x = 3 into the side lengths:

  1. 3xβˆ’4=3(3)βˆ’4=9βˆ’4=53x - 4 = 3(3) - 4 = 9 - 4 = 5 feet
  2. x2βˆ’1=(3)2βˆ’1=9βˆ’1=8x^2 - 1 = (3)^2 - 1 = 9 - 1 = 8 feet
  3. 2x2βˆ’15=2(3)2βˆ’15=2(9)βˆ’15=18βˆ’15=32x^2 - 15 = 2(3)^2 - 15 = 2(9) - 15 = 18 - 15 = 3 feet

Awesome! All the side lengths are positive, so x=3x = 3 seems like a winner!

Calculating the Perimeter

Now that we know x=3x = 3, we can easily find the perimeter by adding up the side lengths:

P=5+8+3=16P = 5 + 8 + 3 = 16 feet

So, the perimeter of the triangular stage prop is 16 feet. Kat will need enough reflective orange paint to cover 16 feet of edging. Great job, Kat!

Putting it All Together

Let's recap what we did. We started with expressions for the sides of a triangle, figured out the constraints on 'x' to make those sides positive, found a suitable value for 'x,' and then calculated the perimeter. This is a classic example of how math can be used to solve real-world problems. Whether you're painting a stage prop, building a fence, or designing a garden, understanding perimeter is super handy!

So, next time you see a triangle, you'll know exactly how to find its perimeter. Keep those math skills sharp, and you'll be ready for anything life throws your way!

Conclusion

In conclusion, finding the perimeter of a geometric shape involves understanding the relationships between its sides and applying algebraic principles to solve for unknowns. This problem demonstrated how to determine the perimeter of a triangle given expressions for its sides, emphasizing the importance of ensuring all side lengths are positive and satisfying the triangle inequality theorem. By setting up and solving inequalities, we found a valid value for 'x' and subsequently calculated the perimeter, showcasing a practical application of mathematical concepts in real-world scenarios. Remember, math is not just about numbers and equations; it's a powerful tool that helps us understand and interact with the world around us. Keep exploring, keep learning, and keep having fun with math!